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Or with drag: F = m(dv/dt) = k*(dx/dt)^n , Where k is a constant, and n is some power. So we have average earth gravity F = g, so the net force is going to be: -g + k*(dx/dt)^(n) = The net acceleration. Having an n term as a power makes it not generally solvable, so you model whatever is closest....usually an "n" of two for spheres. Anyone following? ...Anyone? I am so alone...

You said the force and acceleration equations are the same. You've gotta divide the force equation by the falling man's mass first before you get the acceleration. Bonus points to anyone who can tell me what the motion equations for the chunks of gore at the end of the animation are.

gr33n, thats simple. Just look back at Caruso's Theorem.